using System;
using System.Text.RegularExpressions;
public class EntryPoint
{
static void Main( string[] args ) {
// Create regex to search for IP address pattern.
string pattern = @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
@"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
@"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
@"([01]?\d\d?|2[0-4]\d|25[0-5])";
Regex regex = new Regex( pattern );
Match match = regex.Match( "192.168.169.1" );
while( match.Success ) {
Console.WriteLine( "IP Address found at {0} with " +
"value of {1}",
match.Index,
match.Value );
Console.WriteLine( "Groups are:" );
foreach( Group g in match.Groups ) {
Console.WriteLine( "\t{0} at {1}",
g.Value,
g.Index );
}
match = match.NextMatch();
}
}
}
Output
IP Address found at 0 with value of 192.168.169.1
Groups are:
192.168.169.1 at 0
192 at 0
168 at 4
169 at 8
1 at 12