OpenFileDialog : OpenFileDialog : GUI Windows Forms C# Examples

    
using  System;
using  System.Windows.Forms;

public  class  OpenFileDialogDisplay  {

    public  static  void  Main()  {
    OpenFileDialog  dlgOpen  =  new  OpenFileDialog();
    if  (dlgOpen.ShowDialog()  ==  DialogResult.OK){
        Console.Write(dlgOpen.FileName);
        }
    }
}