Reverse : Regular Expression : Regular Expression C# Examples

Reverse

    
using  System;
using  System.Text;
using  System.Text.RegularExpressions;

public  class  MainClass
{
        static  void  Main(  string[]  args  )  {
                //  Create  regex  to  search  for  IP  address  pattern.
                string  pattern  =  @"(?<part1>[01]?\d\d?|2[0-4]\d|25[0-5])\."  +
                                                  @"(?<part2>[01]?\d\d?|2[0-4]\d|25[0-5])\."  +
                                                  @"(?<part3>[01]?\d\d?|2[0-4]\d|25[0-5])\."  +
                                                  @"(?<part4>[01]?\d\d?|2[0-4]\d|25[0-5])";
                Regex  regex  =  new  Regex(  pattern  );
                Match  match  =  regex.Match(  "192.168.123.1"  );

                string  replace  =  @"${part4}.${part3}.${part2}.${part1}"  +
                                                  @"  (the  reverse  of  $&)";
                Console.WriteLine(  regex.Replace("192.168.123.1",  replace)  );
        }
}
    
   
  
   

1.123.168.192 (the reverse of 192.168.123.1)

Related in same category :
• Use Regular Expressions to split string
• Do a replace using the Regex
• Regular Expresion Part
• new Regex('^\\d+') 1
• new Regex('\d+$') 2
• new Regex('^\\d+$') 3
• new Regex('(abc)|(xyz)*') 1
• new Regex('((abc)|(xyz))*') 2
• new Regex('((?
• new Regex(?(^\d)^\d+$|^\D+$)
• new Regex((abc)*)x(\1)
• new Regex(^\d+$\n+, RegexOptions.Multiline)
• new Regex((abc)*abc((abcd)|z)bc)
• new Regex(]+>[^]+>)
• new Regex(]+)>[^