Demonstrate invoking a constructor through this : Constructor : Class Interface C# Source Code

Demonstrate invoking a constructor through this

    

/*
C#: The Complete Reference 
by Herbert Schildt 

Publisher: Osborne/McGraw-Hill (March 8, 2002)
ISBN: 0072134852
*/


// Demonstrate invoking a constructor through this. 
  
using System;  
  
class XYCoord {   
  public int x, y;   
   
  public XYCoord() : this(0, 0) { 
    Console.WriteLine("Inside XYCoord()"); 
  }  
 
  public XYCoord(XYCoord obj) : this(obj.x, obj.y) { 
    Console.WriteLine("Inside XYCoord(obj)"); 
  }  
 
  public XYCoord(int i, int j) {  
    Console.WriteLine("Inside XYCoord(int, int)"); 
    x = i; 
    y = j; 
  }     
}     
     
public class OverloadConsDemo1 {     
  public static void Main() {     
    XYCoord t1 = new XYCoord();   
    XYCoord t2 = new XYCoord(8, 9);   
    XYCoord t3 = new XYCoord(t2);   
   
    Console.WriteLine("t1.x, t1.y: " + t1.x + ", " + t1.y);  
    Console.WriteLine("t2.x, t2.y: " + t2.x + ", " + t2.y);  
    Console.WriteLine("t3.x, t3.y: " + t3.x + ", " + t3.y);  
  }     
}



           
       
    
   
  
   

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