List pop([i])
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![List pop([i])](http://www.navioo.com/Code/PythonImages/Listpopi.PNG) |
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# Remove the item at the given position in the list, and return it. If no index is
# specified, a.pop() removes and returns the last item in the list. The item is
# also removed from the list. (The square brackets around the i in the method
# signature denote that the parameter is optional, not that you should type square
# brackets at that position. You will see this notation frequently in the Python
# Library Reference.)
a = [66.25, 333, 333, 1, 1234.5]
print a.pop(1)
print a
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