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PHP : Function Reference : MySQL Functions : mysql_field_type

mysql_field_type

Get the type of the specified field in a result (PHP 4, PHP 5, PECL mysql:1.0)
string mysql_field_type ( resource result, int field_offset )

Example 1440. mysql_field_type() example

<?php
mysql_connect
("localhost", "mysql_username", "mysql_password");
mysql_select_db("mysql");
$result = mysql_query("SELECT * FROM func");
$fields = mysql_num_fields($result);
$rows   = mysql_num_rows($result);
$table  = mysql_field_table($result, 0);
echo
"Your '" . $table . "' table has " . $fields . " fields and " . $rows . " record(s)\n";
echo
"The table has the following fields:\n";
for (
$i=0; $i < $fields; $i++) {
   
$type  = mysql_field_type($result, $i);
   
$name  = mysql_field_name($result, $i);
   
$len   = mysql_field_len($result, $i);
   
$flags = mysql_field_flags($result, $i);
   echo
$type . " " . $name . " " . $len . " " . $flags . "\n";
}
mysql_free_result($result);
mysql_close();
?>

The above example will output something similar to:

Your 'func' table has 4 fields and 1 record(s)
The table has the following fields:
string name 64 not_null primary_key binary
int ret 1 not_null
string dl 128 not_null
string type 9 not_null enum

Related Examples ( Source code ) » mysql_field_type



Code Examples / Notes » mysql_field_type

18-feb-2006 07:52

This function is broken in 4.4.1 (works fine in 4.3.X).
http://bugs.php.net/35536


harald

The note blow seems incomplete/incorrect. For php 4.3 and mysql 4.x the returned values are:
CHAR, VARCHAR, TINYTEXT, TEXT, MEDIUMTEXT, LONGTEXT, ENUM, SET: string
TINYINT, SMALLINT, MEDIUMINT, INT, INTEGER, BIGINT: int
FLOAT, DOUBLE, DECIMAL, NUMERIC: real
TIMESTAMP: timestamp
YEAR: year
DATE: date
TIME: time
DATETIME: datetime
TINYBLOB, MEDIUMBLOB, LONGBLOB, BLOB: blob
if mysql-field-type seems to return the wrong values, you may encounter an compatibility problem of mysql, php and the libraries you use. Try reinstalling php and mysql.


krang

The field type returns what PHP classifies the data found in the field, not how it is stored in the database; use the following example to retrieve the MySQL information about the field....
$USERNAME = '';
$PASSWORD = '';
$DATABASE = '';
$TABLE_NAME = '';
mysql_connect('localhost', $USERNAME, $PASSWORD)
   or die ("Could not connect");
$result = mysql_query("SHOW FIELDS FROM $DATABASE.$TABLE_NAME");
$i = 0;
while ($row = mysql_fetch_array($result)) {
 echo $row['Field'] . ' ' . $row['Type'];
}


ludwigp

Like mysql_fetch_field, this returns the PHP type, not the MySQL type.

fusionstream

krang at krang dot org dot uk
Condensed version of what KRANG said.
To get info on the MYSQL field type, use this code
<?
$result = mysql_query("SHOW FIELDS FROM db_name");
$i = 1;
while ($row = mysql_fetch_array($result)) { //go through one field at a time
 echo "Field $i: ";
 print_r($row) //display all information about A field which can be accessed thru the "$row" array.
 $i++;
}
?>
Will display something like:
Field 1: Array ( [Field] => SN [Type] => mediumint(8) unsigned [Null] => [Key] => PRI [Default] => [Extra] => auto_increment ) , SN, mediumint(8) unsigned
Field 2: Array ( [Field] => ENTITY_ID [Type] => varchar(20) [Null] => [Key] => [Default] => [Extra] => ) , ENTITY_ID, varchar(20)


fred

In MySQL 4.1.x, the four TEXT types (TINYTEXT, TEXT, MEDIUMTEXT, and LONGTEXT) return 'blob" as field types, not "string".

swalif_mesa

Hmm for the previous comment, note that SHOW FIELDS is an alias of SHOW COLUMNS. Very useful if you need to search the mysql-documentation. Here is the link anyway...
http://www.mysql.com/doc/en/SHOW_DATABASE_INFO.html


mariob

For version 4.3.4, types returned are:
STRING, VAR_STRING: string
TINY, SHORT, LONG, LONGLONG, INT24: int
FLOAT, DOUBLE, DECIMAL: real
TIMESTAMP: timestamp
YEAR: year
DATE: date
TIME: time
DATETIME: datetime
TINY_BLOB, MEDIUM_BLOB, LONG_BLOB, BLOB: blob
NULL: null
Any other: unknown


c dot futterlieb

Additional to the note below:
If you're using the "SHOW FIELDS" syntax, be sure that you're adding the table name instead of the db name in the "FROM" parameter:
<?php
$result = mysql_query("SHOW FIELDS FROM table");
?>
Also possible:
<?php
$result = mysql_query("SHOW FIELDS FROM table.db");
?>
or this:
<?php
$result = mysql_query("DESCRIBE table");
?>
http://dev.mysql.com/doc/refman/5.1/en/describe.html


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