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PHP : Function Reference : String Functions : strpbrk

strpbrk

Search a string for any of a set of characters (PHP 5)
string strpbrk ( string haystack, string char_list )

Example 2460. strpbrk() example

<?php

$text
= 'This is a Simple text.';

// this echoes "is is a Simple text." because 'i' is matched first
echo strpbrk($text, 'mi');

// this echoes "Simple text." because chars are case sensitive
echo strpbrk($text, 'S');
?>

Code Examples / Notes » strpbrk

aidan

This functionality is now implemented in the PEAR package PHP_Compat.
More information about using this function without upgrading your version of PHP can be found on the below link:
http://pear.php.net/package/PHP_Compat


pzb

One undocumented requirement:
If $char_list contains null characters ("\0"), only characters before the null will be used.  While PHP handles nulls in strings just fine, the data is passed to a function that is not null safe.


evan

If you're not looking to duplicate the rest of the string, but instead just want the offset, in the spirit of the str*pos() functions:
<?php
function strpbrkpos($s, $accept) {
 $r = FALSE;
 $t = 0;
 $i = 0;
 $accept_l = strlen($accept);
 for ( ; $i < $accept_l ; $i++ )
   if ( ($t = strpos($s, $accept{$i})) !== FALSE )
     if ( ($r === FALSE) || ($t < $r) )
       $r = $t;
 return $v;
}
?>


jamie dot mcardle

I wanted to use this function to look for an @ in a db entry - didn't work because I don't have this version of PHP yet, but I thought I had my issue licked. Darn it.

user

For PHP versions before 5:
<?php
function strpbrk( $haystack, $char_list )
{
$strlen = strlen($char_list);
$found = false;
for( $i=0; $i<$strlen; $i++ ) {
if( ($tmp = strpos($haystack, $char_list{$i})) !== false ) {
if( !$found ) {
$pos = $tmp;
$found = true;
continue;
}
$pos = min($pos, $tmp);
}
}
if( !$found ) {
return false;
}
return substr($haystack, $pos);
}
?>
Sadly this is about ten times slower than the native implementation.


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