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bcadd
Add two arbitrary precision numbers
(PHP 4, PHP 5)
Example 336. bcadd() example<?php Code Examples / Notes » bcaddbo anders svensson
Be aware: $exp1 = "1E5"; $exp2 = "2E4"; $ans1 = bcadd((float)$exp1, (float)$exp2, 3); $ans2 = bcadd((int)$exp1, (int)$exp2, 3); $ans3 = bcadd($exp1, $exp2, 3); echo "1: $exp1 + $exp2 = $ans1\r\n"; echo "2: $exp1 + $exp2 = $ans2\r\n"; echo "3: $exp1 + $exp2 = $ans3\r\n"; 1: 1E5 + 2E4 = 120000.000 2: 1E5 + 2E4 = 3.000 3: 1E5 + 2E4 = 0.000 |